Fundamentals of Computer Science I: Media Computing (CS151.02 2007F)
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Related Courses:
[CSC151.01 2007F (Davis)]
[CSC151 2007S (Rebelsky)]
[CSCS151 2005S (Stone)]
This lab is also available in PDF.
Summary: In this laboratory, you will experiment with a variety of techniques for transforming RGB colors and images built from RGB colors.
Contents:
Reference:
In this laboratory, you will be creating a few images and manipulating others. We will also be working with some colors.
Create a new 4x3 image, call it canvas
, show it, and zoom
in to 16x resolution.
Open an existing image of your choice, call it picture
, and
show it. Please choose an image that is not too large (say, not much
more than 250x250).
Load your list of favorite colors, /home/username/Desktop/fave-colors.sct
.
If you don't have that file, use /home/rebelsky/glimmer/samples/fave-colors.sct
.
a. Using rgb->rgb-list
or rgb->string
, remind
yourself of the three components of fave1
.
b. Determine what happens to the components when you apply rgb.darker
to fave1
. You'll need to apply rgb.darker
and then find out the components of the new color.
c. Determine what happens when you apply rgb.lighter
to fave1
.
d. Draw three pixels in sequence on canvas
. The first should be the lighter version of fave1
. The second should be fave1
. The third should be the darker version of fave1
. Do you see a difference?
e. What do you expect to happen to the red, green, and blue components if you apply rgb.lighter
three times to the color 127/20/20, as in the following?
(define newcolor (rgb.lighter (rgb.lighter (rgb.lighter (rgb.new 127 20 20)))))
f. Check your answer experimentally.
g. What do you expect to happen to the red, green, and blue components if you apply rgb.darker
three times to the color 127/20/20, as in the following?
(define newcolor (rgb.darker (rgb.darker (rgb.darker (rgb.new 127 20 20)))))
h. Check your answer experimentally.
As you may recall from the reading, there are also color transformations
that make more significant changes to colors. For example,
rgb.phaseshift
shifts each component by 128 (adding to
small components and subtracting from large components). In contrast,
rgb.complement
computes the complement of a color.
Suppose we've defined the following colors:
(define c0 (rgb.new 64 128 196)) (define c1 (rgb.new 32 96 255)) (define c2 (rgb.new 240 0 127))
a. What do you expect the complements of c0
, c1
,
and c2
to be?
b. Check your answer experimentally.
c. What do you expect the phase shifts of c0
, c1
,
and c2
to be?
d. Check your answer experimentally.
a. Set pixels (0,0) and (1,1) of canvas
to
fave1
.
b. Make the top-left pixel darker using the more verbose instruction from the reading.
(image.set-pixel! canvas 0 0 (rgb.darker (image.get-pixel canvas 0 0)))
c. Make the pixel at (1,1) darker using the
the more concise image.transform-pixel!
procedure.
(image.transform-pixel! canvas 1 1 rgb.darker)
d. Do you see any advantages of using the longer instruction?
Of course, rather than computing new pixels from the pixels in one image,
we can also compute them from the pixels in another image. For example,
the following code should put in canvas
a darker version
of the top-left square of some pixels from picture
(image.set-pixel! canvas 0 0 (rgb.darker (image.get-pixel picture 100 100))) (image.set-pixel! canvas 0 1 (rgb.darker (image.get-pixel picture 100 101))) (image.set-pixel! canvas 1 0 (rgb.darker (image.get-pixel picture 101 100))) (image.set-pixel! canvas 1 1 (rgb.darker (image.get-pixel picture 101 101)))
Confirm experimentally that these instructions work as we suggested.
Of course, we can get more transformations by combining the basic transformations. For example, we get a different color when we complement and darken a color than when we complement or darken the color alone.
a. Does the order in which we apply transformations matter? In particular, do you get the same or different color when you complement and then darken a color as compared to when you darken and then complement the color? In code, what is the relationship between newcolor1
and newcolor2
?
(define newcolor1 (rgb.darken (rgb.complement fave1))) (define newcolor2 (rgb.complement (rgb.darken fave1)))
b. Check your answer experimentally.
c. What do you expect to have happen if you complement a color twice, as in this example?
(define newcolor3 (rgb.complement (rgb.complement fave2)))
d. Check your answer experimentally.
e. At first glance, lightening and darkening an image seem to be complements. Are there ever times in which the sequence of lighten and then darken does not give you back the same color?
(define newcolor4 (rgb.darken (rgb.lighten fave3)))
f. Check your answer experimentally. In doing so, try colors near the extremes, such as black, white, yellow, 10/255/127, and such.
In the corresponding reading, there is a set of sample code that is intended to transform canvas
by complementing every pixel.
(image.transform-pixel! canvas 0 0 rgb.complement) (image.transform-pixel! canvas 0 1 rgb.complement) (image.transform-pixel! canvas 0 2 rgb.complement) (image.transform-pixel! canvas 0 3 rgb.complement) (image.transform-pixel! canvas 1 0 rgb.complement) (image.transform-pixel! canvas 1 1 rgb.complement) (image.transform-pixel! canvas 1 2 rgb.complement) (image.transform-pixel! canvas 1 3 rgb.complement) (image.transform-pixel! canvas 2 0 rgb.complement) (image.transform-pixel! canvas 2 1 rgb.complement) (image.transform-pixel! canvas 2 2 rgb.complement) (image.transform-pixel! canvas 2 3 rgb.complement)
a. There is a subtle error in the code. Identify the error and fix it. (If you can't figure out the error, try running the code to see what error messages you get.)
b. Update canvas
so that it has a variety of colors. Here
is one set of simple changes, but you can do what you want.
(image.set-pixel! canvas 0 0 (rgb.new 0 0 0)) (image.set-pixel! canvas 1 0 (rgb.new 255 0 0)) (image.set-pixel! canvas 2 0 (rgb.new 0 255 0)) (image.set-pixel! canvas 3 0 (rgb.new 0 0 255)) (image.set-pixel! canvas 0 1 (rgb.new 255 255 255)) (image.set-pixel! canvas 1 1 (rgb.new 255 0 255)) (image.set-pixel! canvas 2 1 (rgb.new 255 255 0)) (image.set-pixel! canvas 3 1 (rgb.new 0 255 255)) (image.set-pixel! canvas 0 2 (rgb.new 63 127 195)) (image.set-pixel! canvas 1 2 (rgb.new 127 195 63)) (image.set-pixel! canvas 2 2 (rgb.new 195 63 127))
c. Verify that the repaired instructions do, in fact, complement all of the pixels.
d. What do you expect to have happen if you run this code twice?
e. Check your answer to the previous question experimentally.
At first glance, some find that rgb.phaseshift
is a lot like
rgb.complement
. After all, each changes a color by shifting
the components, and adding or subtracting 128 may feel like an easier way
to get something that sums to 255. However, as we've suggested in the reading,
the two operations are quite different.
a. Find two colors whose pseudo-complements are fairly close to their phase-shifted versions. You may find the following code useful as you visually compare the different colors.
(define color1 (rgb.new __ __ __)) (define color2 (rgb.new __ __ __)) (define ps1 (rgb.phaseshift color1)) (define ps2 (rgb.phaseshift color2)) (define comp1 (rgb.complement color1)) (define comp2 (rgb.complement color2)) (image.set-pixel! canvas 0 0 color1) (image.set-pixel! canvas 1 0 ps1) (image.set-pixel! canvas 2 0 comp1) (image.set-pixel! canvas 0 2 color2) (image.set-pixel! canvas 1 2 ps2) (image.set-pixel! canvas 2 2 comp2)
b. Find two colors whose phase-shifted versions are much different than their pseudo-complements.
c. Do you expect there to be more colors like those in a, or more colors like those in b? (That is, is it more likely that the pseudo-complement of a color is close to the phase-shifted color, or that they are different?) Explain your answer.
http://www.cs.grinnell.edu/~rebelsky/Courses/CS151/History/Labs/transforming-rgb.html
.
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Reference:
[Scheme Report (R5RS)]
[Scheme Reference]
[DrScheme Manual]
Related Courses:
[CSC151.01 2007F (Davis)]
[CSC151 2007S (Rebelsky)]
[CSCS151 2005S (Stone)]
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