Functional Problem Solving (CSC 151 2013F) : EBoards
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Current: [Assignment] [EBoard] [Lab] [Outline] [Partners] [Reading]
Sections: [Assignments] [EBoards] [Examples] [Handouts] [Labs] [Outlines] [Partners] [Readings]
Reference: [Setup] - [Functions A-Z] [Functions By Topic] - [Racket] [Scheme Report (R5RS)] [R6RS] [TSPL4]
Related Courses: [Davis (2013F)] [Rebelsky (2010F)] [Weinman (2012F)]
Misc: [SamR] [Glimmer Labs] [CS@Grinnell] [Grinnell] [Issue Tracker (Course)]
Overview
Thinking about insertion sort ... * For a list of length n, we call insert n times * Insert into the empty list * Insert into a list of length 1 * Insert into a list of length 2 * Insert into a list of length 3 * And so and so forth * If we're lucky, insert happens at the front, that's one step Approximately n total calls to cons (or whatever) * If we're unlucky, insert happens at the end * Inserting into a sublist of length k takes about k recursive calls * Overall running time * 0 + 1 + 2 + ... n-1 is approximately (n^2)/2 * If I double the input size and I'm unlucky ... * E.g., if it's 1 minute to sort 100 things, it will take 4 minutes to sort 200 things (2n)^2/2 = 4(n^2)/2 * When we have an inefficient algorithm ... can we do better?
Primary: [Front Door] [Schedule] - [Academic Honesty] [Disabilities] [Email] [FAQ] [IRC] [Teaching & Learning] [Grading]
Current: [Assignment] [EBoard] [Lab] [Outline] [Partners] [Reading]
Sections: [Assignments] [EBoards] [Examples] [Handouts] [Labs] [Outlines] [Partners] [Readings]
Reference: [Setup] - [Functions A-Z] [Functions By Topic] - [Racket] [Scheme Report (R5RS)] [R6RS] [TSPL4]
Related Courses: [Davis (2013F)] [Rebelsky (2010F)] [Weinman (2012F)]
Misc: [SamR] [Glimmer Labs] [CS@Grinnell] [Grinnell] [Issue Tracker (Course)]
Samuel A. Rebelsky, rebelsky@grinnell.edu
Copyright (c) 2007-2013 Janet Davis, Samuel A. Rebelsky, and Jerod Weinman. (Selected materials are copyright by John David Stone or Henry Walker and are used with permission.)

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